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Tju [1.3M]
3 years ago
11

Explain to a new student how a reflection across the y-axis changes the coordinates of the original point.

Mathematics
1 answer:
RSB [31]3 years ago
6 0
If you were to have (3,2) and find the reflection of the y axis, it would turn y into a negative, making it (3,-2).
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Answer:

The first one

Step-by-step explanation:

In mathematics, the term linear function refers to two distinct but related notions: In calculus and related areas, a linear function is a function whose graph is a straight line, that is, a polynomial function of degree zero or one. So going in that order gives you a linear function.

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3. Find the value of x and y.<br> (80 )<br> yo<br> (3x +20)
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cathi scored 6 baskets in each of her last 3 basketball games. Each basket was worth 2 points. how many points did cathi score i
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3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
2 years ago
Find the variable in xy=6b
Mkey [24]
Xy=6b
/y .  /y
x=6by
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