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denis-greek [22]

3 years ago

6

I think the answer is B but I’m not sure

1 answer:

Anestetic [448]3 years ago

7 0

The answer should be A, because when you solve the inequality for x, you get x<3, so ur answer should be everything on the number line less than 3.

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Charlie does the following problem:

Alika [10]

The answer is B. He is incorrect because he should have only 5 factors of 3.

7 0

3 years ago

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Theresa is planning on making a fleece blanket for her nephew. She learns that the fabric she wants to use is $7.99 per yard. Fi

Anastaziya [24]

Answer:

$31.96

Step-by-step explanation:

(7.99)×(4)= $31.96

7 0

3 years ago

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Can someone please help me with this?? please please please help me

Nadya [2.5K]

Step-by-step explanation:

base is 12, hypotenuse is 20

so X² is h²-b²

so X=16

8 0

3 years ago

Please Help me..<br><br>What is the value of x?

Triss [41]

In triangle ABC, angle B is 90° and angle A is 45° => triangle ABC is Isosceles triangle. That means side AB = BC

Also, side AC² = AB² + BC² = 2BC²
(6√2)² = 2BC² => 36*2
BC = 6

In triangle BCD, angle D is 90° and angle B is 60° => triangle BCD is semi Equilateral triangle. That means side BD = ½BC = 6/2 = 3 which is the value of X.

Good luck

3 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago