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igor_vitrenko [27]
3 years ago
6

Subtract. (6-v-25) - (7+-4)

Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

\left(6-v-25\right)-\left(7+\left(-4\right)\right)=-v-22

Step-by-step explanation:

Considering the expression

\left(6-v-25\right)\:-\:\left(7+-4\right)

\left(6-v-25\right)-\left(7+\left(-4\right)\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

6-v-25-\left(7-4\right)

\mathrm{Subtract\:the\:numbers:}\:7-4=3

6-v-25-3

\mathrm{Group\:like\:terms}

-v+6-25-3

\mathrm{Add/Subtract\:the\:numbers:}\:6-25-3=-22

-v-22

Therefore,

\left(6-v-25\right)-\left(7+\left(-4\right)\right)=-v-22

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Debora [2.8K]

Answer:

the side of a square is 45 m

Step-by-step explanation:

The computation of the side of the square field that contains the similar area as compared with rhombus is given below:

As we know that

Area of rhombus = Base × Altitude

= 81 × 25

= 2025

And, area of Square =  Side × side

2025 = side^2

side  = √2025

= 45m

Hence, the side of a square is 45 m

8 0
3 years ago
Combining like term 6k+7k
Nadya [2.5K]
13k is the answer :)
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3 years ago
What is 1875 ÷ 125 (show ur work long divison)
Colt1911 [192]

Answer:

15 R7

Step-by-step explanation:

     <u> 015</u>

32/ 487

      <u>0</u>

      48

      <u>32</u>

      167

      <u>160</u>

remainder 7

7 0
2 years ago
The perimeter of a rectangle is 86cm. Its shortest side has a length of 16cm. State the length of the longest side.
Artyom0805 [142]

Answer: length = 27 cm

Step-by-step explanation:

Perimeter = 2(l + w)

86 = 2(l + 16)

86 = 2l + 32

86 - 32 = 2l

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7 0
3 years ago
Jones figures that the total number of thousands of miles that an auto can be driven before it would need to be junked is an exp
romanna [79]

Answer:

0.3678

Step-by-step explanation:

Jones figures that the total number of thousands of miles that an auto can be driven before it would need to be junked is an exponential random variable with parameter 1/20. Smith has a used car that he claims has been driven only 10,000 miles. If Jones purchases the car, what is the probability that she would get at least 20,000 additional miles out of it?

Given that the total number of thousands of miles(X) that an auto can be driven

before it would need to be junked is an exponential random variable with parameter 1/20.

=> X ≅ Exponential(λ= 1/20)

=> f(x) = 1/20 * e^(-x/20) , 0 < x < ∞

=> F(X) = P{X < x} = 1 - e^(-x/20)

The probability that she would get at least 20,000 additional miles out of it.

P{X > 20} = 1-P{X < 20}

P{X > 20} = 1-(1 - e^(-20/20))

= e^(-1)

= 0.3678

6 0
3 years ago
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