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Ket [755]
3 years ago
15

Jerry is going to paint a circle in his living room. If the radius is 8 inches, what is the area that Jerry needs to cover with

his paint?
(Use 3.14 for π)
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:201.06

Step-by-step explanation:

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Tom has twice as many marbles as luke. together they have 39 marbles. how many marbles does tom have?
irga5000 [103]
Tom has 26 marbles total. 
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2 years ago
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If 3/5 w = 4/3, what is the value of w?
elena55 [62]

Answer:

w=20/9 or w=2 2/9

Step-by-step explanation:

Multiply each side by 5/3. Then reduce the numbers with the greatest common divisor which is 5 do the same with 3. then multiply the fractions and thus the answer of 20/9 you can simplify the improper fraction if you want the answer is still the same. Hope this helps.

5 0
3 years ago
What is the quotient of 0.37394392523
OLga [1]

Answer:

fill in the missing number on the number line

2350 2350

8 0
2 years ago
If cos theta= -8/17 and theta is in quadrant 3, what is cos2 theta and tan2 theta
Karo-lina-s [1.5K]
\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad  
\begin{array}{llll}
\textit{now, hypotenuse is always positive}\\
\textit{since it's just the radius}
\end{array}
\\\\\\
thus\qquad cos(\theta)=\cfrac{-8}{17}\cfrac{\leftarrow adjacent=a}{\leftarrow  hypotenuse=c}

since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side

now, let us use the pythagorean theorem, to find the opposite side, or "b"

\bf c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite
\end{cases}
\\\\\\
\pm\sqrt{17^2-(-8)^2}=b\implies \pm\sqrt{225}=b\implies \pm 15=b

so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means,  -15 = b

so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then

\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
\boxed{1-2sin^2(\theta)}\\
2cos^2(\theta)-1
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-----------------------------\\\\
cos(2\theta)=1-2sin^2(\theta)\implies cos(2\theta)=1-2\left( \cfrac{-15}{17} \right)^2
\\\\\\
cos(2\theta)=1-\cfrac{450}{289}\implies cos(2\theta)=-\cfrac{161}{289}




\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\left( \frac{-15}{-8} \right)}{1-\left( \frac{-15}{-8} \right)^2}
\\\\\\
tan(2\theta)=\cfrac{\frac{15}{4}}{1-\frac{225}{64}}\implies tan(2\theta)=\cfrac{\frac{15}{4}}{-\frac{161}{64}}
\\\\\\
tan(2\theta)=\cfrac{15}{4}\cdot \cfrac{-64}{161}\implies tan(2\theta)=-\cfrac{240}{161}
6 0
3 years ago
What are the coordinates of P??
AnnyKZ [126]

Answer:

97 and 10

Step-by-step explanation:

4 0
2 years ago
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