Answer:
yes
Step-by-step explanation:
The law lets us move all of the addends around in any addition problem.
Answer:x=-15
Step-by-step explanation: Solve for x by simplifying both sides of the equation, then isolating the variable.
(I am very sorry that i couldnt explain more but im too tired to explain it in excruciating detail.)
Answer:
a. 2^(x-2) = g^(-1)(x)
b. A, B, D
Step-by-step explanation:
the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)
1. replace g(x) with y and solve for x
y = log₂(x) + 2
subtract 2 from both sides to isolate the x and its log
y - 2 = log₂(x)
this text is replaced by the second image -- it was marked as inappropriate
thus, 2^(y-2) = x
replace x with g^(-1)(x) and y with x
2^(x-2) = g^(-1)(x)
2. plug this in to points A, B, C, D, E, and F
A: (2,1)
plug 2 in for x
2^(2-2) = 2⁰ = 1 so this works
B: (4, 4)
2^(4-2) = 2²= 4 so this works
C: (9, 3)
2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work
(5, 8)
2^(5-2) = 2³ = 8 so this works
E: (3, 5)
2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work
F: (8, 5)
2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of passengers that rest or sleep during a flight.
The sample taken is n=9 passengers and the probability of success, that is finding a passenger that either rested or sept during the flight, is p=0.80.
I'll use the binomial tables to calculate each probability, these tables give the values of accumulated probability: P(X≤x)
a. P(6)= P(X=6)
To reach the value of selecting exactly 6 passengers you have to look for the probability accumulated until 6 and subtract the probability accumulated until the previous integer:
P(X=6)= P(X≤6)-P(X≤5)= 0.2618-0.0856= 0.1762
b. P(9)= P(X=9)
To know the probability of selecting exactly 9 passengers that either rested or slept you have to do the following:
P(X≤9) - P(X≤8)= 1 - 0.8657= 0.1343
c. P(X≥6)
To know what percentage of the probability distribution is above six, you have to subtract from the total probability -1- the cumulated probability until 6 but without including it:
P(X≥6)= 1 - P(X<6)= 1 - P(X≤5)= 1 - 0.0856= 0.9144
I hope it helps!
<span>(-3 + 3i) + (-6 + 6i) =
= -3 + 3i + (-6) + 6i
= 3i + 6i + (-3) + (-6)
= 9i + (-9)
= 9i - 9
</span>
