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8_murik_8 [283]
4 years ago
8

Please HELP!!! Due tonight and I’m so worried.

Mathematics
2 answers:
adelina 88 [10]4 years ago
7 0

Answer:

3: Line AD

4: Line Segment AD

5: Point H

Step-by-step explanation:

For #3, because plane ABC and AEH are both planes that go in every direction infinitely, All points on line AD intersect.

For #4, because line segment AD is contained inside of the same plane of ABC, The entire line segment intersect.

For #5, Both lines meet at point H.

ExtremeBDS [4]4 years ago
6 0

Answer:

third one should be about f

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Which graph shows y=3⌈x⌉+1 ?
hram777 [196]

The graph located in the upper right corner of the image attached shows the graph of y = 3[x]+1.

In order to solve this problem we have to evaluate the function y = 3[x] + 1 with a group of values.

With x = { -3, -2, -1, 0, 1, 2, 3}:

x = -3

y = 3[-3] + 1 = -9 + 1

y = -8

x = -2

y = 3[-2] + 1 = -6 + 1

y = -5

x = -1

y = 3[-1] + 1 = -3 + 1

y = -2

x = 0

y = 3[0] + 1 = 0 + 1

y = 1

x = 1

y = 3[1] + 1 = 3 + 1

y = 4

x = 2

y = 3[2] + 1 = 6 + 1

y = 7

x = 3

y = 3[3] + 1 = 9 + 1

y = 10

 x     y

-3    -8

-2    -5

-1     -2

0      1

 1     4

 2    7

 3   10

The graph that shows the function y = 3[x] + 1 is  the one located in the upper right corner of the image attached.

7 0
3 years ago
Read 2 more answers
Solve the formula for the indicated variable<br><br> rx + ry = 4 for r
pishuonlain [190]

Answer:

r =   4/(x+y)

Step-by-step explanation:

rx + ry = 4

Factor out r

r ( x+y) = 4

Divide each side by (x+y)

r ( x+y) /(x+y) = 4/(x+y)

r =   4/(x+y)

3 0
3 years ago
4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr
Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single  bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = 3(4)^{5} =3072

ii) II bacteria P = 3(4)^{4} =768

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

3(4)^{10}- 3(4)^{8} =2949120

c) i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

i) P=3 (4)^{36/12}=192

The rate may not be constant for a longer time.  Hence this may not be accurate.

e) when splits into 2, we get

P=P_o (2^t) where P0 is initial and t = interval of time

7 0
4 years ago
A) y=1.1x+23<br> B) y=1.25x+20<br> C) y=1.25+40.67<br> D)y+1.4+40.67
Lunna [17]

Answer:

I believe C is the correct answer because the graph starts above 40 on y axis and D is incorrect because of the y + not y=

7 0
3 years ago
The sum of 3 consecutive numbers equal 87, find the numbers
boyakko [2]

Answer:

28, 29, 30

Step-by-step explanation:

8 0
4 years ago
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