Answer:
ΔABC ≅ ΔEFD by HL
Step-by-step explanation:
The two triangles given, ∆ABC and ∆EFD, are right triangles.
BC in, ∆ABC, is the hypotenuse and has a length of 5 units, which corresponds to hypotenuse, DF, of ∆EFD. DF also has a length of 5 units.
Therefore, BC ≅ DF.
AC in ∆ABC, corresponds to DE in ∆EFD. Both have the same length.
Therefore, AC ≅ DE.
Since we the hypotenuse of both ∆s and 1 of their corresponding legs are equal, we can conclude that both triangles are congruent based on the Hypotenuse-leg congruency statement, which says that if two right triangles have the same hypotenuse length and a corresponding leg that is equal, both triangles are said to be congruent.
Therefore, ΔABC ≅ ΔEFD by HL
