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Lilit [14]
3 years ago
13

Which equation represents a line that passes through (2, –1/2) and has a slope of 3?

Mathematics
2 answers:
KIM [24]3 years ago
8 0
Hello,

y+1/2=3(x-2)
or y=3x-13/2

77julia77 [94]3 years ago
8 0

Answer:

Step-by-step explanation:

Let the equation of the line is y = mx + c

where m = slope = 3

and c = y-intercept

Now the equation of this line will become

y = 3x + c

Since this line passes through (2, \frac{-1}{2})

so  \frac{-1}{2} = 6 + c

c =  \frac{-1}{2} - 6

  =  \frac{-13}{2}

So the line will be y = 3x + \frac{13}{2}

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First let's get the equation 2x - y = -4 into slope intercept form. To do this first subtract 2x to both sides:

2x - 2x - y = -4 - 2x

0 - y = -4 - 2x

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Y still isn't completely isolated, it still has the negative attached to it. To get rid of the negative divide both sides by -1

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slope intercept formula is:

y = mx + b

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b is the y-intercept

For a line that is parallel to y = 2x + 4 and passes through point (2, 5) you will need to have the same slope (2)

This is the formula we know so far for the line parallel to y = 2x + 4:

y = 2x + b

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To do that you must plug in the point the line goes through  ( 2, 5) in the x and y of the equation.

5 = 2(2) + b

5 = 4 + b

Now solve for b by subtracting 4 to both sides

1 = b

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^^^This line is parallel to 2x - y = -4 and goes through the point (2, 5)

Hope this helped!

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5 0
3 years ago
Factor completely 3x4 − 48.
kvasek [131]

Answer:

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Step-by-step explanation:

take

3

x

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Answer:

Step-by-step explanation:

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