Everything thanksss.
2 answers:
You might be interested in
One Way:
We can change the mixed number to a decimal for comparing.
m = 
m = 1.25 m
1.4 m > 1.25 m
Darren > Luke
Darren's jump was higher by (1.4-1.25) 0.15 m
Or another way change the decimal to a fraction and the mixed to an improper fraction too.
= (Luke)
1.4 =
(Darren)
We need a common denominator to compare
(Luke)
(Darren)
(Luke)
(Darren)
Darren > Luke
By:
- = 
Which is also by 0.15 m
Darren jumps higher and by 0.15 m
We can change the mixed number to a decimal for comparing.
1.4 m > 1.25 m
Darren > Luke
Darren's jump was higher by (1.4-1.25) 0.15 m
Or another way change the decimal to a fraction and the mixed to an improper fraction too.
1.4 =
We need a common denominator to compare
Darren > Luke
By:
Which is also by 0.15 m
Darren jumps higher and by 0.15 m
Hello,
Let's be
![z=2x^4+8x \\ dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\ \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\ = 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}= \left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648](https://tex.z-dn.net/?f=%20z%3D2x%5E4%2B8x%20%5C%5C%0Adz%3D%288x%5E3%2B8%29%5C%20dx%3D8%28x%5E3%2B1%29%5C%20dx%20%5C%5C%0A%0A%20%5Cint%5Climits%5E0_%7B-1%7D%20%7B%282x%5E4%2B8x%29%5E3%2A%284x%5E3%2B4%29%7D%20%5C%2C%20dx%20%3D4%2A%20%5Cint%5Climits%5E0_%7B-6%7D%20%7B%20%5Cdfrac%7Bz%5E3%7D%7B2%7D%7D%20%5C%2C%20dz%20%5C%5C%0A%3D%202%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D%0A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D0-648%3D-648)
Let's be