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kherson [118]
2 years ago
8

Given the following functions:

Mathematics
1 answer:
Ivahew [28]2 years ago
7 0

Answer:

Step-by-step explanation:

g(f(x)) = g(x²) = x²- 3

f(g(x)) = f(x-3) = (x-3)² = x²+ 6x + 9

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The functions f(x) and g(x) are shown on the graph.f(x) = 1x1What is g(x)?f(x) = x1g(x) = ?A. g(x) = x + 3B. g(x) = x + 3O c. g(
Tema [17]

Given function is

f(x)=\lvert x\rvert

Consider the functionj

\lvert x\rvert-3

In the given graph, the point at 0 is (0,-3)

Hence the function corresponding to the given graph is

g(x)=\lvert x-3\rvert

Hence the answer is C. since x=0, then

\lvert x\rvert-3=-3
7 0
1 year ago
Plz help me with 1,2 , and 3 im giving 50 points for it!
butalik [34]

Answer:

1: x > -5

2: n > 4

3: x > -2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
5. If "h" is positive how does the parabola move? If negative?
Paul [167]

Answer: positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

Step-by-step explanation: Note that the value for h is subtracted from x, and then this difference is squared. See that positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

7 0
3 years ago
Solve #5<br> Is the equation that you use<br> P(t)=P(0)•e^rt ?
Elan Coil [88]
P(t)=(p jk(t)),0 ~ t< 0
5 0
3 years ago
In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

5 0
3 years ago
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