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Nataly_w [17]
3 years ago
8

Evaluate the expression for q = -2. 8q=

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

-16

Step-by-step explanation:

8q

Let q = -2

8*-2

-16

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PLZ HELP!!!
slava [35]

Answer: Senior: $8, Child: 14

Step-by-step explanation:

3s + c = 38

3s + 2c = 52

c = 14

3s + 14 = 38

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2 years ago
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Factor x2+4x+3.
Alexxx [7]

Answer:

c. (x +3)(x + 1)

Step-by-step explanation:

Factoring an equation is a way of expressing an equation as the product of other linear expressions. The following expression,

x^2 +4x +3

Can be represented as the product of the following,

(x+3)(x+1)

To check this, one can distribute, one of the expressions over the other, then simplify, the result should be the starting expression,

(x+3)(x+1)\\

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Simplify,

x^2 +x +3x + 3\\

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2 years ago
The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
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therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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