Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
Answer: 5b + 3 - b -b - 4
Step-by-step explanation:i think thats the answer pls mark brainliest
<span>Let x be the number of songs downloaded.
Each song is $1.29; the total cost would be found by multiplying the cost by the number of songs, or 1.29x.
This cannot be more than 20, so we set this less than or equal to 20:
1.29x ≤ 20.
<u>To solve this, we divide both sides by 1.29: </u>
</span>

<span> ≤ </span>

<span>;
x ≤15.5.
We <u>cannot download half of a song</u>, so we round this down to 15 (although the number rounds up mathematically, he would not have enough money to download 16 songs). This means he can download at most 15 songs.</span>
Answer:
4 
Step-by-step explanation:
The additive inverse is the value that must be added to the number to give zero.
- 4
+ 4
= 0
↑ additive inverse