2 years ago

Solve the quadratic equation y^2 −10y+21=0 y=?

Mathematics

1 answer:

Firdavs [7]2 years ago

8 0

Answer: y = 3 or y=7

Step-by-step explanation:

$y^{2} -10y+21$

what 2 factors of 21 can equal 10 when added together (1*21- no 3*7- yes)

Factor

$(y-3)(y-7)$

y-3=0

y=3

or y-7=0

y=7

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Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

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