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Georgia [21]
3 years ago
6

Kerri correctly calculated the distance between point S (–3428) and point T (286) on a number line.

Mathematics
1 answer:
kogti [31]3 years ago
6 0
Ok, you're dealing with a 1 dimensional number line.

To find the distance between these two points what you want to do is go from -3428 to 0, then from 0 to 286.

The distance between -3428 and 0 is 3428. The distance from 0 to 286 is 286.

Add up both these differences:

3428 + 286 = 3714

So the answer is in fact D, 3714.
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siniylev [52]
48 + (2*13) / 110
PE(MD)(AS)

2 * 13 = 26
48 + 26 / 110

26 / 110 = 0.236..
Rounded = 0.24

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6 0
2 years ago
Acqueline reads 25 pages every night. Which graph correctly displays y, the total number of pages that Jacqueline has read after
mrs_skeptik [129]

Answer:

On a coordinate plane, a graph titled Total Pages Jacqueline Has Read has days on the x-axis and Pages on the y-axis. A line goes through points (1, 25) and (2, 50).

Step-by-step explanation:

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3 years ago
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the distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way.
Sholpan [36]

The distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way. The distance ezra runs can be solve by multiplying 8/10 to the total distance.

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3 years ago
Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x - 6)2(x + 2)2
Tpy6a [65]
<span>The number of x-intercepts that appear on the graph of  the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)


Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0

Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2

(x-6)^2=0
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sqrt[ (x-6)^2] = sqrt(0)→x-6=0
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(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
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3 years ago
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Brums [2.3K]

Answer:

I wanna say its D. $259.67

Step-by-step explanation:

Some one should back my answer but I hope this helps you

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