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zubka84 [21]
3 years ago
14

Money is put into two accounts. Account A earns 3.5% interest annually, and account B eanrs 2.6% interest annually. Assuming $20

,000 is split evenly among the accounts and interest is not compounded, how much interest would be earned in total after 6 years?
Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

$3360 combined. $1560 from acct b and $2100 from acct a

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The fair will be traveling to a place that uses the metric system. They received directions to their next stop, but they are in
MariettaO [177]

Answer:

2x - 0.4x ;

8x/5 ;

Yes

Step-by-step explanation:

Let number of miles = x

Arlene:

Double number of miles = 2 * x = 2x

Subtract 20% of the result :

2x - 20% of 2x ;

2x - 0.4x

Raul:

Divides Number of miles by 5 ; x / 5

Multiplies result by 8 ;

8 * (x/5) = 8x /5

To know if expressions are equivalent :

Let x = 10 miles

Using Arlene's expression:

2x - 0.4x

x = 10

2(10) - 0.4(10) = 16

Using Raul's expression :

8x / 5

(8*10) / 5

80/5

= 16

Since they give the same result, we can conclude that the expression are equivalent

5 0
3 years ago
4 2 5 0<br>3 2 8 7<br>2 1 8 ?​
natali 33 [55]

Answer:

5

Step-by-step explanation:

7 0
2 years ago
the GCF of two numbers is 850 number is divisible by the other what is the smallest these two numbers can be
Nuetrik [128]
If you're trying to say one number is divisible by the other, the two numbers are ...
  1*850 = 850
  2*850 = 1700
4 0
3 years ago
A train has 10 cars numbered 1 through 10. If the cars are coupled randomly, what is the probability that the first3 cars are in
Pepsi [2]

You would have a 3 to 10 chance that the first 3 cars are in order


8 0
3 years ago
Read 2 more answers
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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