The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.
In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.
The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)
E = 2% = 0.02
Confidence level = 90%
Now, the proportion is not given so adopt nominal (p-vector) = 0.05
The critical value at CL of 90% is 1.645.
Thus, making n the subject,
n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)
n = 1.645²((0.5 × 0.5) ÷ 0.02²)
n = 1691.266
n ≈ 1691
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Answer:
45 dogs
Step-by-step explanation:
so she has $550 and she did 20 cats and it costs $5 per cat and 5 x 20 is $100 and $550 - $100 = 450 and 450 divided by 10 ( because it's $10 per dog) is 45.
So since we know what x is, we can substitute it into the original equation for x like so to solve for y...
(2y - 8) + 5y - 10 = 0
2y - 8 + 5y = 10
2y + 5y = 18
7y = 18
y = 18/7 (or about 2.57)
So now we know what x is, we can sub it into the below equation to solve for x...
x = 2(18/7) - 8
x = 36/14 - 8 (or about -5.43)
Answer:
13
Step-by-step explanation:
Sorry i cannot showy solution
