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Free_Kalibri [48]
3 years ago
8

Mr. Chang’s class has 28 students, StartFraction 4 Over 7 EndFraction of whom are girls. Which equation shows how to determine t

he number of girls in Mr. Chang’s class? 28 divided by StartFraction 4 Over 7 EndFraction = 49 28 times StartFraction 4 Over 7 EndFraction = 16 StartFraction 4 Over 7 EndFraction divided by 28 = StartFraction 1 Over 49 EndFraction StartFraction 7 Over 4 EndFraction divided by 28 = StartFraction 1 Over 16 EndFraction
Mathematics
2 answers:
Olegator [25]3 years ago
7 0

Answer:

Okay, so we know a number of students and the amount of girls as a bracket. So what we have to do now is multiply them with each other.

28 *4/7 = 16

So there are 16 girls in Mr. Chang´s class.

You can also determine the boys by - the students with the girls:

28-16=12 boys

Have a nice day :D

Step-by-step explanation:

brainliest?

ANTONII [103]3 years ago
7 0

Answer:

Step-by-step explanation:

Okay, so we know a number of students and the amount of girls as a bracket. So what we have to do now is multiply them with each other.

28 *4/7 = 16

So there are 16 girls in Mr. Chang´s class.

You can also determine the boys by - the students with the girls:

28-16=12 boys

hope that helped lol

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Find the point P on the parabola y=x^2 closest to the point (3,0).
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In parallelogram ABCD, line AC is congruent to line BD. Is ABCD a rectangle?
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  A.  yes

Step-by-step explanation:

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A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin
maks197457 [2]

Answer:

(a) \sum x_i=56.68 and \sum x_i^2=197.46

(b) The sample variance is s^2=0.530 and the sample standard deviation is s=0.728

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68

and the sum of their squares is

\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46

(b)

The sample variance, denoted by s^2, is given by

s^2=\frac{S_{xx}}{n-1}

where S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}

Applying the above formula we get that

S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482

s^2=\frac{8.482}{17-1}=0.530

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

s=\sqrt{s^2}

Applying the above formula we get that

s=\sqrt{0.530}=0.728

3 0
3 years ago
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