Answer:
I belive the answer is 5
Step-by-step explanation:
Answer:
Simplifying the expression
we get 
Step-by-step explanation:
We need to simplify the expression 
Solving:

Applying exponent rule: 

Factors of 
Factors of 
Replacing terms with factors

Using exponent rule: 

Using exponent rule: 

Now using exponent rule: 

So, simplifying the expression
we get 
Answer:
2 , 1\2
Step-by-step explanation:
b² - 4ac = (-5)² - 4*2*2
= 25 - 16
= 9

![x= \dfrac{-[-5] + 3}{2*2} ; x = \dfrac{-[-5]-3}{2*2}\\\\x =\dfrac{5+3}{4} ; x = \dfrac{5-3}{4}\\\\x=\dfrac{8}{4} ;x = \dfrac{2}{4}\\x = 2 ; x = \dfrac{1}{2}](https://tex.z-dn.net/?f=x%3D%20%5Cdfrac%7B-%5B-5%5D%20%2B%203%7D%7B2%2A2%7D%20%3B%20%20x%20%3D%20%5Cdfrac%7B-%5B-5%5D-3%7D%7B2%2A2%7D%5C%5C%5C%5Cx%20%3D%5Cdfrac%7B5%2B3%7D%7B4%7D%20%3B%20x%20%3D%20%5Cdfrac%7B5-3%7D%7B4%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B8%7D%7B4%7D%20%20%3Bx%20%3D%20%5Cdfrac%7B2%7D%7B4%7D%5C%5Cx%20%3D%202%20%3B%20x%20%3D%20%5Cdfrac%7B1%7D%7B2%7D)
Answer:
-4,-2,-1
Step-by-step explanation:
The next term is going to be the previous number divided by two
Answer:
there are 11 big-bags and 24 small-bags.
Step-by-step explanation:
there are x big-bags and y small-bags.
so now we can know:
(1) x + y = 35
(2) 12x + 7y = 300
in (1),we can do like this:
both left and right x7
then (x + y)x7 = 35 x 7
then 7x + 7y = 35 x 7
then 7x + 7y = 245
now,
(1)7x + 7y =245
(2)12x + 7y = 300
we can both left and right do this: (2) - (1)
then
(12x + 7y) - (7x + 7y) = 300 -245
then
12x + 7y - 7x - 7y = 300 -245
then
12x - 7x +7y - 7y =300 -245
then
5x =55
then
5x ÷ 5 = 55 ÷ 5
then
x = 11
because
x + y =35;x=11
so
11 + y =35
11+ y -11 = 35 -11
then
y = 24
now we know:there are 11 big-bags and 24 small-bags.