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3 years ago

Put the following in order from the smallest to the largest 0.2 1/2 2%

Mathematics

2 answers:

Keith_Richards [23]3 years ago

4 0

2%, 0.2, 1/2 hope I helped

aliya0001 [1]3 years ago

3 0

Answer:

2%, 0.2, 1/2

Step-by-step explanation:

0.2 = 0.20 = 20%

1/2 = 0.50 = 50%

2% = 0.02

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A certain forest covers an area of 2100 km^2. Suppose that each year this area decreases by 5.25%. What will the area be after 6

Neko [114]

Answer:

The area after 6 years is $1519.49km^2$

Step-by-step explanation:

Given

$a = 2100$ --- Initial Value

$r = 5.25\%$ --- Rate

Required

Determine the area after 6 years

Because the area reduces,, the following formula will be used to solve the question.

$y = a*(1 - r)^t$

Here

$t = 6$

So, we have:

$y = 2100*(1 - 5.25\%)^6$

Convert percentage to decimal

$y = 2100*(1 - 0.0525)^6$

$y = 2100*(0.9475)^6$

$y = 1519.47866516$

$y = 1519.49$ -- approximated

The area after 6 years is $1519.49km^2$

4 0

2 years ago

I just can't do thissssssssss

mel-nik [20]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

So, since the given slope is -3/4, the negative reciprocal is $\frac{4}{3}$ .

We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$