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mina [271]
3 years ago
5

The selling price of a house dropped from $250,000 to $210,000 over a period of 5 years. what percent did the selling price decr

ease?
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

sorry I haven't learned how to do that yet


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Jane is building a tank for her pet snake. The tank’s minimum length should equal two-thirds of the snake’s length, and the tank
Studentka2010 [4]
The dimensions should be 1  2/3 feet by   1  1/2 feet.

To find these amounts, we simply multiply the length of the snake by the given fraction.

For the length, multiply by 2/3.

For the width, multiply by 1/2.
4 0
2 years ago
Use an inequality symbol (<,>,=,<_) to compare -3+7____-10-2
Oliga [24]

Answer:

>

Step-by-step explanation:

-3+7= 4

-10-2= -12

4> -12

6 0
3 years ago
Sample size: A researcher is trying to decide how many people to survey. Which of the following sample sizes will result in a co
oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given that a researcher is trying to decide how many people to survey.

We have confidence intervals are intervals with middle value as the mean and on either side margin of error.

Confidence interval = Mean ± Margin of error

Thus confidence interval width depends on margin of error.

Margin of error = Critical value *\frac{\sigma}{\sqrt{n} }

Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.

Hence for small n we get wide intervals.

So if sample size = 300, the researcher will get wider confidence interval

4 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
HELPP ME WITH 1,2,3 pleaseeeeeee
sattari [20]
2: (360-50-50)/2=130 degrees
5 0
2 years ago
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