The answer would be y = 2 over 3x - 4
Answer:
This statement is sometimes true
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
RM298
reason: multiply RM4 by 10 to get RM40 and add that to RM258 to get RM298
The distance from A to B is the radius, as point A is the center of the circle, and B is a point on the circle.
AB is 5 inches, so the radius will be 5 inches.
D is another point on the circle, so AD would also be considered a radius. This means that the distance from A to D would be 5 inches.
