Question

There are two teams of students: team A with 3 sophomores, 8 juniors and 13 seniors; and team B with 5 sophomores, 7 juniors and 6 seniors. Suppose we pick one student from each team at random. Find the probability that both students are of the same type (that is, both sophomores, or both juniors, etc).

Answer 1

Answer:

sopomores= 0.0397

juniors= 0.1481

seniors= 0.2063

Explanation:

Giving the following information:

There are two teams of students:

Team A with 3 sophomores, 8 juniors, and 13 seniors. Total of 24 students.

Team B with 5 sophomores, 7 juniors, and 6 seniors. Total of 18 students.

First, we need to calculate the probability of selecting any student on each team:

Team A:

sophomores=3/21= 0.1428

juniros= 8/21= 0.3809

senors= 13/21= 0.619

Team B:

sopomores= 5/18= 0.2778

juniors= 7/18= 0.3889

seniors= 6/18= 0.3333

Now, we can calculate the probability of selecting the same type of students:

sopomores= 0.1428*0.2778= 0.0397

juniors= 0.3809*0.3889= 0.1481

seniors= 0.619*0.3333= 0.2063