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3 years ago

7

Factor the trinomial x^2+6x-16

1 answer:

vagabundo [1.1K]3 years ago

7 0

For quadratics with an a value (coefficient of x²) of 1, we find factors of c, the constant, that sum to b, the coefficient of x. In our case we want factors of -16 that sum to 6.
-16 = -1(16) or 16(-1)
-16 = -2(8) or 8(-2)
-16 = -4(4) or 4(-4)

Out of these 6 possibilities, the only one that sums to 6 is 8(-2), because 8+(-2)=6.

This gives us the factors (x+8)(x-2).

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Step-by-step explanation:

Given:

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Now by using Pythagoras theorem which states that;

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<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

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Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

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