There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
First, find a common denominator (the bottom number) Then add the tops as usual. Four and five have a common denominator of 20 so: 8/20+5/20=13/20
Answer:
The frequency does not change with more trials
Step-by-step explanation:
To predict: the probability of the coin landing heads up
Solution:
Probability refers to the chances that an event will occur in an experiment. The value of probability lies between 0 and 1. 0 indicates impossible event and 1 indicates a sure event. The probability of an event can not be greater than 1.
When a coin is tossed, there are two possible outcomes: heads (H), tails (T).
In case of the probability of the coin landing heads up, the frequency does not change with more trials.
Answer:
2.06
Step-by-step explanation:
3x102=306
6×105=630
630 ÷ 306 = 2.0588235294
round it to 2.06
Answer:
Answer is D.
30
Step-by-step explanation:
all angles add up to 180(applys to triangles)
