Answer:
If k = −1 then the system has no solutions.
If k = 2 then the system has infinitely many solutions.
The system cannot have unique solution.
Step-by-step explanation:
We have the following system of equations
The augmented matrix is
The reduction of this matrix to row-echelon form is outlined below.
The last row determines, if there are solutions or not. To be consistent, we must have k such that
Case k = −1:
If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.
Case k = 2:
This gives the infinite many solution.