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adelina 88 [10]
3 years ago
10

I will give you brainliest

Mathematics
1 answer:
vovangra [49]3 years ago
6 0

I believe the answer should be graph J

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Coach Stevens needs to purchase sprinklers to water the baseball field. The standard distance between bases is 90 feet and the i
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If you need the geometry and trigonometry I'll post those.  Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span> <span> <span> 66.78</span> </span>f</span>eet

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Seven blue and four red balls are to be arranged in order. How many ways can this be done if (1) The blue balls are distinguisha
Sav [38]

Answer:

1) n = 39916800

2) n = 1663200

3) n = 330

Step-by-step explanation:

1) If the blue balls are distinguishable as are the red balls

Then you can arrange these balls in the following ways, we must use a permutation

In totally we have 11 balls, then

n = 11P11

n = \frac{11!}{(11-11)!} = 11! = 39916800\\  

2) If Blue balls are distinguishable, but the red balls are identical

In this case, we need to do a correction due to the red balls are identical and we cannot identify the difference when we interchange two red balls

n = \frac{11!}{4!}  = \frac{39916800}{24} = 1663200

3) If the balls of each color are indistinguishable

We proceed equal to the before case but we include a correction due to blue balls also

n = \frac{11!}{4!*7!} = \frac{39916800}{24*5040} = 330

7 0
3 years ago
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