1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dima020 [189]
3 years ago
9

Mrs. drennan keeps a bag of small prizes to distribute to her students. She likes to keep at least three times as many prizes in

the bag as she has students. the bag currently has 72 prizes in it. Mrs. drennan has 26 students what is the least amount of prizes Mrs Drennan needs to buy ?
Mathematics
2 answers:
Ber [7]3 years ago
8 0
26x3=78
78-x=72
x=6
She needs to buy at least 6 more to have enough for 26 students

adelina 88 [10]3 years ago
6 0

Answer:

The least amount of prizes Mrs Drennan needs to buy = 6

Step-by-step explanation:

She likes to keep at least three times as many prizes in the bag as she has students.

If number of students is n, number of prizes she has = 3 n

Given that Mrs. drennan has 26 students

That is n = 26

Number of prizes needed = 3n = 3 x 26 = 78

Number of prizes she has = 72

Minimum prizes she need to buy = 78 - 72 = 6

The least amount of prizes Mrs Drennan needs to buy = 6

You might be interested in
Which statements are true about finding the difference of the expressions? Select three options? 3p + 1/6p - 2p - 3/2p​
kicyunya [14]

Answer: Options 2, 4 and 5

Step-by-step explanation:

E2020 Answers

4 0
3 years ago
Question 8 (1 point)
AleksandrR [38]

Answer:

solution is x=3

Step-by-step explanation:

logx-log3=log(x-2)

apply log property

log a- log b= log a/b

logx-log3=log(x-2)\\log (\frac{x}{3} )=log(x-2)

we have log on both sides

so we remove the log and make the arguments equal

\frac{x}{3} = x-2

solve for x, multiply whole equation by 3

x=3(x-2)\\x=3x-6\\x-3x=-6\\-2x=-6\\x=3

now plug in 3 for x  and check

logx-log3=log(x-2)\\log3-log3=log(3-2)\\0=0

solution is x=3

8 0
3 years ago
Supposed the population of deer in a region was 3,500 in the year 2000.since then population has grown by 3.5% annually. What wi
sergejj [24]
Y = a (b^x)

1) x = 0, y = 3500

=> 3500 = a (b^0)

=> 3500 = a (1)

=> a = 3500

2) growth percent = 3.5% => growth rate = 1.035 = b

=> y = 3500 (1.035)^ x

3) year 2020 => x = 2020 - 2000 = 20

4) y = 3500 (1.035)^ 20 = 6964

Answer: 6964.

3 0
3 years ago
Did you get the answer to this question
Harlamova29_29 [7]
The anser is all of the above please make brainlyleist
4 0
3 years ago
Read 2 more answers
A.0.5×10^4
Juliette [100K]

Answer:

sdd

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • The angle whose measure is StartFraction 3 pi Over 4 EndFraction terminates in quadrant II and its reference angle is for StartF
    11·2 answers
  • I need help understanding how to solve this please ASAP!!!!
    13·2 answers
  • Identify the radius of the circle whose equation is (x - 2)^2 + (y - 8)^2 = 16.
    12·2 answers
  • Charlene bought 4 pounds of pears. She paid for the pairs with a $20 bill and received $9.40 in change. What is the price per po
    5·2 answers
  • A sequence is defined by the equation a1=50 and an=an-1+(-4) what is term a5?
    10·1 answer
  • Write an equation for the translation of y=|x| 8 units left
    5·2 answers
  • The speed v of a gear varies inversely as the number of teeth t. If a gear that has 42 teeth makes 24 revolutions per minute (rp
    15·1 answer
  • When translating the point (5,0) 6 units up and 4 units to the right, we should get:
    6·1 answer
  • PLS HELP ME ILL GIVE BRAINLY
    9·2 answers
  • Solve the system of equations.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!