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4 years ago

What is the answer sir

Mathematics

1 answer:

krek1111 [17]4 years ago

8 0

The question remains: What is your favorite color?

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the increase in a persons body temperature T(t), above 98.6 degrees F, can be modeled by function T(t)=4t/t^2+1, t represents th

ehidna [41]

The horizontal asymptote is the limit of the temperature as time goes to infinity.

If we ignore the constant in the denominator, then
$T = \frac{4t}{t^2} = \frac{4}{t}$

And the limit as t-> infinity is 0
$\lim_{t \to \infty} \frac{4}{t} = 0$

This means the temperature will decrease over time approaching 98.6 in the long run.

4 0

3 years ago

Read 2 more answers

A recent study focused on the amount of money single men and women save monthly. The information is summarized next. Assume that

IgorLugansk [536]

Answer:

Both means are apprxoimately equal at 1% level of significance.

Step-by-step explanation:

Given is the information summarised below

Group Men Women

Mean 23.00 28.00

SD 5.00 10.00

SEM 1.00 1.83

N 25 30

H0: Mean of mean = mean of women

Ha: means of men < mean of women

(Left tailed test)

Since population std deviation is known but sample sizes are small t test is used.

The mean of Men minus Women equals -5.00

standard error of difference = 2.201

t = 2.2721

df = 53

p value= 0.0136

since p >0.01 at 1% significance level we fail to reject H0.

Both means are apprxoimately equal at 1% level of significance.

7 0

4 years ago

What is the interquartile range of the following data set?<br> 290, 357, 380, 413, 395, 313, 335

kolezko [41]

Answer:

123

Step-by-step explanation:

4 0

3 years ago

A computer generates 50 integers from 1 to 5 at random. The results are recorded in the table. What is the experimental probabil

Nastasia [14]

C. The answerr is C because it’s actuate

7 0

3 years ago

The Genetics & IVF Institute conducted a clinical trial of the YSORT method designed to increase the probability of conceivi

Reika [66]

Answer: The test statistic needed to test this claim= 10.92

Step-by-step explanation:

We know that the probability of giving birth to a boy : p= 0.5

i..e The population proportion of giving birth to a boy = 0.5

As per given , we have

Null hypothesis : $H_0: p\leq0.5$

Alternative hypothesis : $H_a: p>0.5$

Since $H_a$ is right-tailed , so the hypothesis test is a right-tailed z-test.

Also, it is given that , the sample size : n= 291

Sample proportion: $\hat{p}=\dfrac{239}{291}\approx0.82$

Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$ , where n is sample size , $\hat{p}$ is sample proportion and p is the population proportion.

$\Rightarrow\ z=\dfrac{0.82-0.5}{\sqrt{\dfrac{0.5(1-0.5)}{291}}}\approx10.92$

i.e. the test statistic needed to test this claim= 10.92

Critical value ( one-tailed) for 0.01 significance level = $z_{0.01}=2.326$

Decision : Since Test statistic value (10.92)> Critical value (2.326), so we reject the null hypothesis .

[When test statistic value is greater than the critical value , then we reject the null hypothesis.]

Thus , we concluded that we have enough evidence at 0.01 significance level to support the claim that the YSORT method is effective in increasing the likelihood that a baby will be a boy.

7 0

3 years ago