question 2. Is Carbohydrates like sugar and starch.
question 3. It is 4 grams for alcohol
question 4. it will be 40-75 percent
hope it is helpful.
from 6th grader Darren
Answer:
Mr. Smith is not justified, Mrs. Smith can not be blamed necessarily for being unfaithful
Explanation:
Widow's peak is a dominant trait which means that it will be expressed both in homozygous and heterozygous condition. If "A" is the dominant allele and "a" is the recessive allele, the trait can be represented as AA or Aa.
Both Mr. Smith and Mrs. smith expressed the trait so they can either have AA or Aa genotype. If even one of them had AA genotype all the offspring would have the trait. But if both of them are heterozygous for it:
A a
A AA Aa
a Aa aa
There is 75 % probability of the child to have the trait (AA or Aa) but there is also 25% probability that the child does not express the trait (aa). Their second child belongs to this category and hence Mrs. Smith can not be blamed for being unfaithful.
I think it is natural selection. genetic variation also could be a factor for physical variation over the years.
I suggest, if this is a laptop given to you for school purposes, that you search through all the things downloaded on the laptop. You may find a screen sharing device or an application on the computer that allows the school to monitor your screen or what you've accessed. If you don't find anything of the sort downloaded on the computer you may be fine, although i would suggest doing small things at first, like scrolling through images or having multiple tabs open, so if it turns out they can see your screen you wont get in too much trouble. If nothing happens you may be fine. I do online school on my own laptop and no ones stopped me from tabbing around during lessons, but who knows. Good luck, fam.
