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maks197457 [2]
2 years ago
10

How to solve this using rational equations

Mathematics
1 answer:
Reptile [31]2 years ago
5 0

Answer:

Step-by-step explanation:

look this solution :

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Write the inequality represented by the graph
enot [183]
The answer is: X < 1
4 0
3 years ago
Explain how you can use a model to find 6 x 17
crimeas [40]
We can use partial products model to solve 6×17
here Multiplicand =6
Multiplier=17
First break Multiplier (17) into 1 ten and 7 ones as
17=10+7
Then Multiply 6 to both of the parts of 17 then add it,
6×17
=6(10+7)
=6×10+6×7 [Distributive property]
=60+42=102
Partial Product is a product obtained by multiplying the multiplicand by one digit of the multiplier when the multiplier has more than one digit.
7 0
3 years ago
X+2(x+3(x+4(x+5)))=153
Allushta [10]

Answer:

x=1

Step-by-step explanation:

Here first open the inner parentheses and use the distributive property,

4(x+5)=4x+20\\\\(x+4(x+5))=(x+4x+20)=(5x+20)\\\\3(x+4(x+5))=3(5x+20)=15x+60\\\\(x+3(x+4(x+5)))=(x+15x+60)=16x+60\\\\2(x+3(x+4(x+5)))=2(16x+60)=32x+120\\\\x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\\Hence\ x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\Rightarrow 33x+120=153\\\\33x=153-120\\\\33x=33\\\\x=1

3 0
2 years ago
Imagine the United States only had two postage stamps, a 3 cent stamp and a 7 cent stamp. If you can put any number of stamps on
cricket20 [7]

Answer:

  • not possible:  1, 2, 4, 5, 8, 11
  • possible: all others

Step-by-step explanation:

Obviously, all multiples of 3 and 7 can be paid.

1 cent can be added by adding a 7-cent stamp and taking away two 3-cent stamps. 2 cents can be added by adding three 3-cent stamps and taking away one 7-cent stamp. Hence any value more than 7 +2(3) = 13 cents can always be accommodated.

Amounts that are impossible:

  1, 2, 4, 5, 8, 11 cents

All other positive integer amounts are possible.

7 0
3 years ago
Five times a number subtracted from 18 is triple the number find the number
Bess [88]
The number is 18

hope this helps
4 0
3 years ago
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