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Kryger [21]
3 years ago
14

At full price, Melvin would pay 1.6791.6791.679 dollars per liter of gasoline. Using his loyalty card, Melvin only pays 1.4391.4

391.439 dollars per liter. How much less does Melvin pay per liter using his loyalty card?
Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer:

Melvin pays 0.24 dollars less using the loyalty card.

Step-by-step explanation:

We are given that,

Original price payed by Melvin = 1.679 dollars per liter

Using the loyalty card, He pays = 1.439 dollars per liter

So, the difference in the amount of money paid by Melvin is,

Difference = Original price - Price using loyalty card

i.e. Difference = 1.679 - 1.439 = 0.24 dollars

Hence, Melvin pays 0.24 dollars less using the loyalty card.

MrRissso [65]3 years ago
3 0

Answer:

Melvin paid 0.24 dollars less per liter, or 14.29% less respect to the full prices

Step-by-step explanation:

Full price: 1.679 dollars per liter

With loyalty card: 1.439 dollars per liter

So, Melvin paid 1.679 - 1.439 = 0.24 dollars less per liter. In percentage term, this represents a discount of (0.24/1.679)*100 = 14.29% respect to the full prices.

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Read 2 more answers
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

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3 years ago
A boat leaves the harbor entrance and travels 28 miles in the direction N 43° E. The captain then turns the boat 90° and travels
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Answer:

Step-by-step explanation:

A boat leaves the harbor entrance and travels 28 miles in the direction N 43° E.

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= 28 cos43 i + 28sin43j

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The captain then turns the boat 90° and travels another 15 miles in the direction S 47° E

Displacement

= 15 cos47 i - 15 sin47 j

= 10.22 i - 10.97 j

Total displacement

= 20.47 i + 19.1 j + 10.22 i - 10.97 j

= 30.69 i - 8.13 j

Magnitude of displacement

= 31.75 miles

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TanФ = - 8.13 / 30.69

Ф = 15 degree  south of east.

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schepotkina [342]

Answer: C. x-2

Step-by-step explanation:

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Factoring in the numerator:

\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}

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x-2

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