The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.
Before being able to solve for energy, need to convert nanometers to meters.
407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m
Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)
E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms
E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)
E = 4.89 x 10^-33 J
This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J
0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34
1.83435583 × 10-34m4 kg2 / s4 photons
Answer:
1 and 2
Explanation:
The given equation is:
Cl₂ + H₂ → 2HCl
A coefficient is the variable or number before a chemical specie.
In this reaction Cl₂ and H₂ are the reactants;
The coefficient of Cl₂ is 1,
H₂ is 1,
HCl is 2
The subscript is the number to the lower power after a chemical specie is denoted.
For Cl₂, it is 2
Answer:
M
Explanation:
The concentration of the analyte in the 5-mL flask would be M
This is a problem of simple dilution that can be solved using the dilution equation;
C1V1 = C2V2,
where C1 = initial concentration, V1 = initial volume, C2 = final concentration, and V2 = final volume.
<em>In this case, the initial concentration (C1) is not known, the initial volume (V1) is 1.00 mL, the final concentration is 6.97 x 10-5 M, and the final volume is 10.00 mL.</em>
Now, let us make the initial concentration the subject of the formula from the equation above;
C1 = C2V2/V1. Solve for C1 by substituting the other parameters.
C1 = 6.97 x 10-5 x 10/1 = M
