<h3>You will pay $ 30876800</h3>
We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:
<h3 />
Density of gold = 19298 oz/ft³
Volume of gold = 1 ft³
<h3>Mass of gold =?</h3>
Density = mass /volume
19298 = mass / 1
<h3>Mass of gold = 19298 oz</h3>
Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:
1 oz = $ 1600
Therefore,
19298 oz = 19298 × 1600
19298 oz = $ 30876800
Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800
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Answer:
mass of kI = 74.55 Atomic mass
74.55 g ---> 1 mole
48.9 g --> ?
48.9 / 72
0.7 mole.
In one mole of kI --->
<span>Answer:
ince 2,4-dimethylpentan-3-ol is symmetrical there will only be one product formed after dehydration. It is 2,4-dimethyl-2-pentene</span>
The answer to this question is A
The volume (in liters) of the sand that must be placed to keep the mass sensitive trap from activating is 0.667 L
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
With the above formula, we can determine the volume of the sand. Details below:
<h3>How to determine the volume of the sand</h3>
- Mass of sand = 2 Kg = 2 × 1000 = 2000 g
- Density of sand = 3 g/cm³
- Volume of sand =?
The volume of the sand can be obtained as follow:
Density = mass / volume
Thus,
Volume = mass / density
Volume of sand = 2000 / 3
Volume of sand = 666.67 cm³
Divide by 1000 to express in liter
Volume of sand = 666.67 / 1000
Volume of sand = 0.667 L
Thus, the volume of the sand is 0.667 L
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