Answer : The concentration of
ion, pH and pOH of solution is,
, 1.05 and 12.95 respectively.
Explanation : Given,
Concentration of
ion = 0.090 M
pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.
The expression used for pH is:
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
First we have to calculate the pH.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)


The pH of the solution is, 1.05
Now we have to calculate the pOH.

The pOH of the solution is, 12.95
Now we have to calculate the
concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![12.95=-\log [OH^-]](https://tex.z-dn.net/?f=12.95%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=1.12\times 10^{-13}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.12%5Ctimes%2010%5E%7B-13%7DM)
The
concentration is, 
Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:

The amount of salt needed for the calculated amount of seawater is:

Erosion by water and earthquakes
Answer:
Sorry
Explanation:
Sorry this is not chemistry but I always try to answer but this time I can't I am so so sorry