Answer:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) is the probability that given that a student has a visa card, they also have a master card
p(A/B) is the probability that given a student has a master card, they also have a visa card
e. 0.35
f. 0.31
Step-by-step explanation:
a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)
=0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76
b. P(AnBnC')= P(AnB)-P(AnBnC)
=0.3-0.07= 0.23
c. P(B/A)= P(AnB)/P(A)
=0.3/O.6= 0.5
e. P((AnB)/C))= P((AnB)nC)/P(C)
=P(AnBnC)/P(C)
=0.07/0.2= 0.35
f. P((AUB)/C)= P((AUB)nC)/P(C)
=(P(AnC) U P(BnC))/P(C)
=(0.11+0.1)/0.2
=0.21/0.2 = 0.31
Answer: 
Step-by-step explanation:
Confidence interval for population mean is given by :-
(1)
, where 
= Sample mean
= Critical z-value
= Population standard deviation.
n= Sample size.
As per given , we have
n= 610
Significance level for 85% confidence : 
By z-table critical two tailed z-value : 
Put all values in (1) , we get
Hence, the 85% confidence interval for the mean consumption of meat among people over age 40. =
Answer:
Step-by-step explanation:
-5,-3,-2,-1,0,1,3,4,6
Answer: 3/4
Step-by-step explanation:
1. square root the denominator and nominator, 36= 6 and 64= 8
2. put them together (6/8)
3. simplify 6/8
4. 6/8 divided by 2
5. 3/4 is your answer
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