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ss7ja [257]
2 years ago
14

I beg anybody please

Mathematics
1 answer:
statuscvo [17]2 years ago
4 0

Answer:

if no one answers pic b cuz i got good luck

Step-by-step explanation:

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Find the lateral area of the regular prism with height h, if the base of the prism is: Equilateral triangle with the side 4 cm a
Shtirlitz [24]

Equilateral triangle with the side 4 cm and h=2.5 cm

In equilateral triangle all sides are equal

so all sides are equal in the base of the prism

lateral area of the prism = Perimeter of the base * height

Perimeter of the base equilateral triangle = side + side + side

lateral area of the prism =(side + side + side) * height

= (4+4+4) * 2.5

= 30 cm^2

lateral area of the prism = 30 cm^2

6 0
2 years ago
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Which of the following shows 2 + (x + 3y) rewritten using the Associative Property of Addition?
Eduardwww [97]
The answer is B. (2 + x) + 3y.

The associative change happened when they just moved the parenthesis.

Hope this helps!
8 0
3 years ago
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How do you subtract 42 minutes from 1 hour ,25 minutes.explain what to do and why you do it?
aksik [14]
So 1 hour= 60 minutes
60+25= 85 minutes
Now we should subtract the 42
85-42=43
3 0
2 years ago
5) Which graph shows the solution of the system of inequalities 2x - y<-6 and y < 2x - 3?
liq [111]

Answer:

B

Step-by-step explanation:

4 0
2 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
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