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Semenov [28]
3 years ago
5

What is one value that makes the fraction (x^2 + 11x +30)/(4x + 44x^2 + 120x) Undefined?

Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Answer:

-31/11

Step-by-step explanation:

To get the value they makes the fraction undefined, we shall need to equate the denominator to zero

Hence;

4x + 44x^2 + 120x

Divide through be x

4 + 44x + 120 = 0

44x = -124

x = -124/44

x = -62/22

x = -31/11

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your gym membership cost $33 per month after an initial membership fee. you paid a total of $228 after 6 months. writer an equat
grin007 [14]

Answer:

what i did was multiply 33*6 and got 198 and then 228-198 to find out that the initial fee was 30 dollars. then multiply 33*9+30 to get a  9-month total cost of $327

Step-by-step explanation:

cost = $33 per month + fee  

1.  c(m) = 33m + f

 33(6) + f = 228

198 + f = 228

f = $30 membership fee  

c(m) = 33m + 30

 2.  at 9 months:  33(9) + 30 = $327

hopefully this helps :)

have a nice day !!

7 0
3 years ago
A rectangular carpet is 2 times as long as it is wide. Its width is 5
rewona [7]

Answer:

30 units

Step-by-step explanation:

If the w=5 and we know that the length is 2(5)=10

For perimeter, there are two sides.

2(10)+2(5)=30 units

7 0
2 years ago
Read 2 more answers
After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu
valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

<u><em>Let p = proportion of all living alumni who favored firing the coach</em></u>

SO, Null Hypothesis, H_0 : p = 0.50   {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, H_A : p > 0.50   {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p  = sample proportion of the alumni in the sample who were in favor of firing the coach = \frac{64}{100} = 0.64

            n = sample of alumni = 100

So, <em><u>test statistics</u></em>  =  \frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }

                               =  2.92

<u>Now, P-value of the hypothesis test is given by ;</u>

         P-value = P(Z > 2.92) = 1 - P(Z \leq 2.92)

                                             = 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0
4 years ago
The probability that a certain kind of component will survive a shock test is 3/4. Find the probability that exactly 2 of the ne
Marina86 [1]

Answer:

Therefore the required probability is =\frac{27}{128}

Step-by-step explanation:

The probability of success is \frac{3}{4}

The number of trial = 4

X= the items survive out of 4

P(x=r)=^nC_rq^{n-r}p^r        p =the probability of success and q = the probability failure.

p=\frac{3}{4}     and q=(1-\frac{3}{4})=\frac{1}{4}

\therefore P(X=2)=^4C_2(\frac{1}{4} )^2(\frac{3}{4} )^2

                  =\frac{4!}{2!2!} (\frac{1}{16} )(\frac{9}{16} )

                  =\frac{27}{128}

Therefore the required probability is =\frac{27}{128}

3 0
4 years ago
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