Question

(3-4i)/(4-5i) HELP ME PLEASE --- algebra 2 question i = the square root of -1 (<<

Answer 1

Answer:

Step-by-step explanation:

Multiply bu the conjuguate of the demonimator.

$\dfrac{3-4i}{4-5i} \\\\\\=\dfrac{(3-4i)(4+5i)}{(4-5i)(4+5i)} \\\\\\=\dfrac{12-16i+15i+20x}{16-i^2*25} \\\\\\=\dfrac{32-i}{41} \\\\\\=\dfrac{32}{41} -\dfrac{i}{41}$