Divide 20x^2y^2+4xy^2-8y^2/4x^2y

Mathematics

1 answer:

Ksivusya [100]3 years ago

7 0

I hope this helps you

[20x^2/4x^2y]+[4xy^2/4x^2y]-[8y^2/4x^2y]

[5/y]+[y]-[4y/x^2]

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