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PtichkaEL [24]
3 years ago
15

What is 0.11 / 22.77

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
6 0

Answer:

is your answer

0.00483091

Step-by-step explanation:

8_murik_8 [283]3 years ago
4 0

Answer: 0.00483

Step-by-step explanation:

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What is the factorization of the polynomial below? -x^2-15x-54
amid [387]
To factor a polynomial we need to find 2 numbers that add up to -15 and multiply into -54.
(-x -18)(x +3) Will be your answer.
8 0
3 years ago
What are the numbers from least to greatest based on the -7 ,4, -2, 3
Anastaziya [24]

Answer:

<em>It would be -7,-2,3,4.</em>

8 0
2 years ago
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The equation y = 1725 - 75x represents the amount of money y (in dollars) left in your lunch account after x weeks. 20 weeks go
garik1379 [7]
Y= -75x +1725
y= -75(20) +1725
y = -1500 + 1725
y= 225 = range
225= -75x +1725
225 - 1725= -75x
-1500=-75x
-1500/-75 = -75x/-75
x = 20 = domain
6 0
3 years ago
Help!!!
choli [55]

Answer:

Step-by-step explanation:

y - 5 > 2x - 10 \\\ y > 2x - 10 + 5 \\\ y > 2x - 5

If x = 0:

y > 2 × 0 - 5

y > - 5

If x = 3:

y > 2 × 1 - 5

y > 1

The coordenates (3, 1) and (0, -5) are not included.

Alternative A

I hope I helped you.

5 0
3 years ago
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A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
11 months ago
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