Answer:
16x^2-24xy+9y^2.
Step-by-step explanation:
Since this is in the form of (x-y)^2, we can plug it into x^2-2xy+y^2.
So, we get 16x^2-24xy+9y^2.
Y = 2x - 6 => slope is 2
For perpendicular lines, m2 = -1/m1
Slope of the required line is -1/2
Required equation is (y - 3)/(x - 0) = -1/2 => y - 3 = -1/2 x => y = -1/2 x + 3
Perimeter = 2( Length + Width)
<em>Given that Perimeter = 3 1/12 feet and Width = 2/3 foot, plug the values into the formula to find the length:</em>
3 1/12 = 2( Length + 2/3)
3 1/12 = 2Length + 4/3
2 Length = 3 1/12 - 4/3
2 Length = 7/4
Length = 7/4 ÷ 2
Length = 7/4 x 1/2
Length = 7/8
<em>Now that we know the length is 7/8 and the width is 2/3, find the area:</em>
Area = Length x Width
Area = (7/8)(2/3) = 7/12
Answer: Area = 7/12 ft²
