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anyanavicka [17]
4 years ago
6

Do the table and the equation represent the same function?

Mathematics
1 answer:
VARVARA [1.3K]4 years ago
6 0
The table indicates a y-value of 115 when x = 0. That corresponds to the y-intercpt of the equation.

The table values increase by 64 for each increase of 2 in x-value. That corresponds to the slope (32) of the equation.

Yes, the equation and the table represent the same function.
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Identify the GCF for he given set 23 and 115 A. 1 B. 23 C. 11
s344n2d4d5 [400]

Answer:

b. 23

Step-by-step explanation:

Using factor trees

23                              115

∧                                 ∧

1  23                           5  23

So,

23= 23

115= 23

If you circle the common factors in each factor tree, you get 23.

Therefore your answer is B

3 0
3 years ago
Read 2 more answers
Slope is –2 &amp; (5, 3) is on the line.<br> Y-Intercept:<br> Equation of the line (no spaces):
GREYUIT [131]

Answer:

The y intercept is (0,13)

The equation of the line is y = -2x+13

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = -2x+b

Substituting the point

3 = -2(5) +b

3 = -10 +b

Add 10 to each side

13 =b

The y intercept is (0,13)

The equation of the line is y = -2x+13

5 0
3 years ago
Divide 2.875x10^6by2.3x10^3
DerKrebs [107]

Answer:

1875L = 1.875x10^6 mL

multiply by density to get 2.14x10^6

multiply by percentage to get 6.63x10^4 g of NaCl (66.3 kg)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write thirty divided by five 3 ways
viktelen [127]

Answer:

30 divided by 5

\frac{30}{5}

5⟌30

Hope this helps!

7 0
4 years ago
8/9 Divided by 6/9 = ?<br> A. 17/54<br><br><br> B. 16/27<br><br><br> C. 4/3<br><br><br> D. 24/5
AleksAgata [21]

Answer:

4/3

Step-by-step explanation:

\frac{8}{9}  \div  \frac{6}{9}  \\  \\  \implies \:  \frac{8}{9}  \times  \frac{9}{6}  \\  \\  \implies \:  \frac{8}{1}  \times  \frac{1}{6}  \\  \\  \implies \:   {\boxed {\purple{\frac{4}{3} }}}

4 0
3 years ago
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