Answer:
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6.
Step-by-step explanation:
Departure time = 0540 Hours means 5: 40 am or 40 minutes past 5 in the morning.
Now add 45 mins
Hours : Minutes
5: 40
<u> + 45</u>
<u> 5 : 85</u>
<u />
But 1 hour contains 60 minutes so 85 - 60 gives 25 minutes . those 60 minutes = 1 hour are carried over the hours and added .
Hours : Minutes
1
5: 40
<u> + 45</u>
<u> 6 : 25</u>
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6 in the morning.
Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,
![cos\alpha= 5/13](https://tex.z-dn.net/?f=cos%5Calpha%3D%205%2F13)
[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= ![+ or -\sqrt{1-(cos\beta) ^{2}](https://tex.z-dn.net/?f=%2B%20or%20-%5Csqrt%7B1-%28cos%5Cbeta%29%20%5E%7B2%7D)
[by general trigonometry formula:
]
so if
, we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
your not suposed to do questions from your testtttttt
Step-by-step explanation:
Answer:
Quinn did not make a mistake. This is because everything she did is correct and also if we calculate the expression without doing anything she did, we see that she has the right answer.