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Galina-37 [17]
3 years ago
14

1.Give at least two characteristics for the rhombus.

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0
1. opposite sides are equivalent , opposite angles are equivalent
2. 4 sides, 4 angles, both answers for number one also work
3. A square
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The sum of 15 and Rhonda's age is 62.
ycow [4]

Answer:

I guess the que is wrong

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4 0
2 years ago
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Factor the expression by finding the GCF. 16m2 − 12m
ziro4ka [17]

Answer:

4m(4m-3)

Step-by-step explanation:

16m^2 − 12m

16 m^2 = 2*2*2*2*m*m

12m = 2*2*3*m

The greatest factor for 16m^2 and 12m is 2*2*m  or 4m

Factor out 4m

16 m^2 = 2*2*2*2*m*m = 4m(2*2m)=4m(4m)

12m = 2*2*3*m = 4m(3)

Factoring out 4m

16m^2 − 12m

4m(4m-3)

3 0
3 years ago
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PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
What is the correct factorization of<br> 6x2 + 24x?<br><br> Hurry
blagie [28]

Answer:

6x^2*(x+4)

Step-by-step explanation:

hope this helps! :)

4 0
3 years ago
2
svet-max [94.6K]

Answer:

 B.  4200

Step-by-step explanation:

A suitable calculator can add the terms for you. (See attached)

__

The first term is 69, and the common difference is 75-69 = 6. The general term is ...

  an = a1 +d(n -1)

  an = 69 +6(n -1)

Then the 28th term is ...

  a28 = 69 +6(27) = 231

The average term is (a28 +a1)/2 = (231 +69)/2 = 150.

The sum is the number of terms multiplied by the average term:

  sum = 28×150= 4200

5 0
2 years ago
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