Answer:
55.75
Step-by-step explanation:
find the area of 1 side using the base and height and divide that answer by 2
5x6=30 30 divided by 2=15
all sides are equal so each side is 15
the base you do the same thing.
base is 5, height is 4.3
4.3 x 5= 21.5
divide it by 2 10.75
side 1=15
side 2= 15
side 3=15
base 1= 10.75
add all together
55.75
The area of a rectangle is the product of its dimensions
The dimensions of the rectangle are: 
and 
The area is given as:
Express 125 as 5^3
Apply difference of cubes
The area of a rectangle is:
So, by comparison:
Read more about areas at:
brainly.com/question/3518080
Answer:
4 2/3 cm
Step-by-step explanation:
When we have area, it is the related to the scale factor by the scale factor squared
Area large/ area of small = 49/9
Take the square root
sqrt(49/9) = 7/3
The scale factor is 7/3 large to small
The small side is 2 cm
large 7 x cm
-------- = ------ = -----------
small 3 2 cm
Using cross products
7*2 = 3x
Divide by 3
14/3 = 3x/3
14/3 = the large side
4 2/3 cm
Once the rock hits the ground, we know that its height will be equal to 0m
because of this, we can replace H(x) with 0
now all we have to do is get x by itself
so..
then
now take the square root of each side
2.857 seconds (rounded to the third decimal)
A quadrilateral is a kite if the diagonals are:
i) perpendicular
ii) bisect each other
iii) not equal ( together with conditions i and ii this would make the quadrilateral a square)
Another definition of the kite is :
a quadrilateral with 2 pairs of equal adjacent sides.
Let's check the choices one by one:
A. <span>∠M is a right angle and MK bisects ∠LMJ.
according to these, ML and MJ may well be not equal...
</span><span>B. LM = JM = 3 and JK = LK = √17.
</span>
this makes the quadrilateral a kite.
<span>C. MK intersects LJ at its midpoint
</span>
if they are not perpendicular, the quadrilateral is not a kite.
<span>D. The slope of MK is –1 and the slope of LJ is 1.
this only means that MK and LJ are perpendicular, but not whether they bisect each other,
Answer: only B</span>
