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larisa86 [58]
3 years ago
10

Question partpointssubmissions usedthe base of a circular fence with radius 10 m is given by x = 10 cos(t), y = 10 sin(t). the h

eight of the fence at position (x, y) is given by the function h(x, y) = 3 + 0.03(x2 − y2), so the height varies from 0 m to 6 m. suppose that 1 l of paint covers 100 m2. determine how much paint you will need if you paint both sides of the fence. (round your answer to two decimal places.)
Mathematics
1 answer:
Anettt [7]3 years ago
8 0

If you unroll the fence, you find it has a length equal to the circumference of a circle of radius 10 m and an average height of 3 m. Its two-sided area will be

... A = 2·(3 m)·(2π·(10 m)) = 120π m²

Then the amount of paint required is

... (120π m²) × (1L)/(100 m²) = 1.2π L ≈ 3.77 L

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Step-by-step explanation:

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Answer:

Perpendicular

<em />

Step-by-step explanation:

Given

A = (-4, 8)

B = (4, 10)

C = (1, 1)

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Required

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First, we need to calculate the slope (m) of AB and CD

m = \frac{y_2 - y_1}{x_2 - x_1}

For AB:

A (x_1,y_1)= (-4, 8)

B(x_2,y_2) = (4, 10)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{10 - 8}{4 - (-4)}

m = \frac{10 - 8}{4 +4}

m = \frac{2}{8}

m = \frac{1}{4}

For CD:

C(x_1,y_1) = (1, 1)

D(x_2,y_2) = (-2, 13)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{13 - 1}{-2 - 1}

m = \frac{12}{-3}

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For Lines to be parallel, the slope must be equal:

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This condition is not true because:

\frac{1}{4} \neq -4

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m_1 = -\frac{1}{m_2}

This implies:

\frac{1}{4} = -\frac{1}{-4}

\frac{1}{4} = \frac{-1}{-4}

\frac{1}{4} = \frac{1}{4}

<em>Hence, the lines are perpendicular</em>

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