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larisa86 [58]
4 years ago
10

Question partpointssubmissions usedthe base of a circular fence with radius 10 m is given by x = 10 cos(t), y = 10 sin(t). the h

eight of the fence at position (x, y) is given by the function h(x, y) = 3 + 0.03(x2 − y2), so the height varies from 0 m to 6 m. suppose that 1 l of paint covers 100 m2. determine how much paint you will need if you paint both sides of the fence. (round your answer to two decimal places.)
Mathematics
1 answer:
Anettt [7]4 years ago
8 0

If you unroll the fence, you find it has a length equal to the circumference of a circle of radius 10 m and an average height of 3 m. Its two-sided area will be

... A = 2·(3 m)·(2π·(10 m)) = 120π m²

Then the amount of paint required is

... (120π m²) × (1L)/(100 m²) = 1.2π L ≈ 3.77 L

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Answer:

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defon
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First, cancel 2 on both sides. / Your problem should look like: d = -3(d - 5) - 2
Second, expand. / Your problem should look like: d = -3d + 15 - 2
Third, simplify -3d + 15 - 2 to get -3d + 13. / Your problem should look like: d = -3d + 13
Fourth, add 3d to both sides. / Your problem should look like: d + 3d = 13
Fifth, add d + 3d to get 4d. / Your problem should look like: 4d = 13
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Answer as fraction: d =  \frac{13}{4}
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4 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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