Answer:
A)29 and B) 21,
Step-by-step explanation:
First,in the sequence
, the parameter
must to be a integer.
Second, we need to solve the equations by
.

All the option in the problem represent an
Then, we need to prove all number in the options, if the result is a integer number, this option can be part of the sequence.
For A)

For B)

For C)

For D)

Only A) and B) only A and B meet the requirement
Remember for any two polygons
Area of polygons is directly proportional to square of sides
So
- BC²/XY²=135/15
- 15²/XY²=9
- (15/3)²=XY²
- XY=5in
#35
- HJ²/XY²=168/378
- 8²/XY²=0.44
- XY²=64/0.44
- XY²=145.45
- XY\approx 12+
Answer:
Step-by-step explanation:
sorry i tried my best i think its like a 30
Answer:
x = 10
Explanation:
Note the following rules before we begin:
2 ln(a) = ln (a²)
ln (a) + ln (b) = ln (ab)
Now, for the given:
ln(20) + ln(5) = 2 ln(x)
ln(20*5) = ln(x²)
ln(100) = ln(x²)
This means that:
100 = x²
Therefore:
either x = 10 .........> acceped
or x = -10 .........> rejected as no negatives are allowed within ln functions
Hope this helps :)