Center at (h,k) and radius r is
(x-h)²+(y-k)²=r²
so given
center at (9,-8)
(x-9)²+(y-(-8))²=r²
(x-9)²+(y+8)²=r²
input the point (19,22) to find r²
x=19 and y=22
(19-9)²+(22+8)²=r²
10²+30²=r²
100+900=r²
1000=r²
10√10=r
well, the equation is
(x-9)²+(y+8)²=1000
Answer:
B. The system of equations has no solution.
Step-by-step explanation:
Parallel lines never touch, in order for a system of equation to have a solution the two equations have to intersect, because parallel lines never intersect the system of equations that Presley graphed would have no solution
<span>The incenter is equidistant from all three triangle sides.
So, PJ = PK = PL.
PJ = 4x -8
PL = x + 7
Therefore,
</span>4x -8 = <span>x + 7
3x = 15
x = 5
So, PJ = 12
PL = 12 and
PK = 12
</span>
2 and 3 are the base angles because they are across from the legs (the 2 equal sides).
If you round 5.066 to the nearest hundredth it would be 5.07
