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vampirchik [111]
4 years ago
15

We can find the roots of a quadratic function by looking at where it intercepts the x-axis. If a graph is entirely above the x-a

xis and never intersects it, what would you infer about the roots of the function?
Mathematics
1 answer:
nexus9112 [7]4 years ago
8 0

Answer:

It doesn't have any roots

Step-by-step explanation:

If the parabola doesn't intersect the x-axis, then there are no solutions to the equation.

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How many seconds in 35 minutes
topjm [15]
All you have to do is multipy the amount of minutes by 60 seconds because there are 60 seconds in every minute.
35 minutes x 60 seconds
2100 secods
3 0
3 years ago
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WILL GIVE BRAINLIEST <br> 4<br> 3<br> 2x + 4<br> x+7
Mariulka [41]

Answer:

x = 8

Step-by-step explanation:

\frac{x+7}{3} =\frac{2x+4}{4}

do cross multiplication

3(2x+4) = 4(x+7)\\6x + 12 = 4x + 28\\6x - 4x = 12 - 16\\2x = 16\\x = 16/2\\x = 8

3 0
3 years ago
The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in in
Grace [21]

Answer:

A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Step-by-step explanation:

We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;

68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2,  76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.

Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;

                             P.Q.  =  \frac{(n-1) \times s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s = sample standard deviation = \sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} } = 5.063

            \sigma = population standard deviation

            n = sample of observations = 22

Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.

<u>So, 90% confidence interval for the population standard deviation, </u>\sigma<u> is ;</u>

P(11.59 < \chi^{2}__2_1 < 32.67) = 0.90  {As the critical value of chi at 21 degrees  

                                                  of freedom are 11.59 & 32.67}  

P(11.59 < \frac{(n-1) \times s^{2} }{\sigma^{2} } < 32.67) = 0.90

P( \frac{ 11.59}{(n-1) \times s^{2}} < \frac{1}{\sigma^{2} } < \frac{ 32.67}{(n-1) \times s^{2}} ) = 0.90

P( \frac{(n-1) \times s^{2} }{32.67 } < \sigma^{2} < \frac{(n-1) \times s^{2} }{11.59 } ) = 0.90

<u>90% confidence interval for</u> \sigma^{2} = [ \frac{(n-1) \times s^{2} }{32.67 } , \frac{(n-1) \times s^{2} }{11.59 } ]

                                     = [ \frac{21 \times 5.063^{2}  }{32.67 } , \frac{21 \times 5.063^{2}  }{11.59 } ]

                                     = [16.48 , 46.45]

<u>90% confidence interval for</u> \sigma = [\sqrt{16.48} , \sqrt{46.45} ]

                                                 = [4.06 , 6.82]

Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

5 0
3 years ago
Help me with work = brainlist
notka56 [123]

Answer:

13 is 90

14 is 43

15 is 146

7 0
4 years ago
45 pts! consider this quadratic equation. x^2+3=4x. Which expression correctly sets up the quadratic formula to solve the equati
Murljashka [212]

Answer:

A.

Step-by-step explanation:

7 0
3 years ago
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