Volumen of A Solid
Given a solid with a shape of a constant base B and height H, the volume is:
V = BH
The height of the solid is 1 1/4 ft. We need to calculate the area of the base.
The base consists of a larger rectangle from which has been taken a smaller rectangle.
The larger rectangle has dimensions of 9 ft by 6 ft, thus its area is:
A1 = 9 ft * 6 ft = 54 square ft
The smaller rectangle has dimensions of 2 1/2 ft by 4 ft.
The second dimension was calculated as the difference between 9 ft and 2 ft plus 3 ft. (9 ft - 3 ft - 2 ft = 4 ft).
The area of the smaller rectangle is:
A2 = 2 1/2 * 4
The mixed fraction 2 1/2 is converted to improper fraction:
2 1/2 = 2 + 1/2 = 5/2
Thus, the area is:
A2 = 5/2 * 4
A2 = 10 square feet
The area of the base is A1 - A2 = 54 square feet - 10 square feet = 44 square feet
B = 44 square feet.
Now for the volume:
V = 44 square feet * 1 1/4 feet
Again the mixed fraction is converted to a single fraction:
1 1/4 = 1 + 1/4 = 5/4
V = 44 square feet * 5/4 feet
V = 55 cubic feet
Answer:
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Step-by-step explanation:
The given equation is:
t = 7 + 5q
where:
t is the total number of points
q is the questions answered correctly
We are given that the total of correct answers is 6 and we want to find the total number of points. Therefore, all we have to do is substitute with the number of answers in the given equation to get the total points as follows:
t = 7 + 5q
t = 7 + 5(6)
t = 7 + 30
t = 37 points