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Triss [41]
3 years ago
13

rac{100}{1000} = {10}^{x} " alt=" \frac{100}{1000} = {10}^{x} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
AURORKA [14]3 years ago
5 0
Exact Form:
X=1/100

Decimal form:
X=0.01
Reika [66]3 years ago
4 0
X=10
You should get the app Photomath! I use that app all the time.
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Please help me with this
Marysya12 [62]

Answer:

SAS is the answer.........

5 0
3 years ago
What’s the least common multiple of 12 and 2
NNADVOKAT [17]

For example, for LCM (12,30) we find:

Using the set of prime numbers from each set with the highest exponent value we take 22 * 31 * 51 = 60. Therefore LCM (12,30) = 60.

7 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
What is the domain and range please?
Vinvika [58]

Answer:

domain is the max and min x values

range is the max and min y values

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help please asap i<br> show step by step !
pychu [463]

Answer:

a = 4\sqrt{3}

b= 4

Step-by-step explanation:

It's a 30-60-90 triangle based on the given picture. A right triangle too

Use sine, cosine, and tangent to solve for the side.

To find b, you can use sin(30) = b/8 because sin(angle) = opposite/hypotenuse.

OR you can use the rule for 30-60-90 triangle, which is x for short leg, 2x for hypotenuse, and x\sqrt{3} for long leg

So either way, b = 4

To find a, you can use cos(30) = a/8 because cos(angle) = adjacent/hypotenuse.

OR you can use the same rule, 30-60-90 triangle to save time

a will end up = 4\sqrt{3}

6 0
3 years ago
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