Given:
Level 1 : Length = 5 ft ; Width = 2 ft
Level 2 : Length = 6 ft ; Width = 2 ft
Level 3 : Length = 4 ft ; Width = 2 ft
Area = L x W
Level 1 = 5 ft * 2 ft = 10 ft²
Level 2 = 6 ft * 2 ft = 12 ft²
Level 3 = 4 ft * 2 ft = <u> 8 ft²</u>
Total Area 30 ft²
Outdoor carpet should measure 30 square feet to cover the hole.
I hope this helps you
x=2/3
g (2/3)=(2/3)^2-2/3
g (2/3)= 4/9-2.3/3.3
g (2/3)=4/9-6/9
g (2/3)= -2/9
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Answer
................. 60 seconds.. in a minute
Step-by-step explanation:
The amount of time of what?
Answer:
22.77%
Step-by-step explanation:
4351-3360 / 4351 x 100 = 22.77%
