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3 years ago

14

I need help on this question pls

1 answer:

Neporo4naja [7]3 years ago

5 0

56/64 = 7/8

7/8 x 120

105.

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What is 2x=8a+2b; solving for x

Eddi Din [679]

Answer:

Step-by-step explanation:

Flip the equation 1) 8a + 2b = 2x

Subtract 2b from both sides 2)8a + 2b(-2b) =<em> 2x + (-2b)</em>

Divide by 8 on both sides 3) 8a/8 =<em> -2b - 2x/8</em>

4) a = 1/-4b + 1/4x

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3 years ago

All 3,000 seats in a theater are being replaced. So far, 5 sections 136 seats and a sixth section containing 348 seats have been

Ostrovityanka [42]

1,124 seats still need to be replaced.

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3 years ago

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(2n + 3)(n – 4) = 0<br> need help asap!!!

Anastaziya [24]

Set each binomial equal to zero to solve.

2n + 3 = 0
2n = - 3
n = - 3 / 2

n - 4 = 0
n = 4

So n = -3/2, 4

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3 years ago

Please help will give lot of points

Nana76 [90]

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C

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A

Step-by-step explanation:

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7 0

3 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

Read more at:

brainly.com/question/14320476

7 0

3 years ago